Bianca Andreescu, Tommy Paul advance to fourth spherical at Miami Open

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MIAMI GARDENS, Fla. — Bianca Andreescu of Canada — the 2019 U.S. Open champion — beat 2020 Australian Open winner Sofia Kenin of the United States 6-4, 6-4 within the third spherical of the Miami Open on Sunday.

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Andreescu superior to the fourth spherical of the Miami Open for the third time. She had seven aces to Kenin’s one and double-faulted solely as soon as as she gained the third straight matchup between the Grand Slam champions. Andreescu transformed all three of her break alternatives.

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In different matches, Ekaterina Alexandrova of Russia defeated world No. 9 Belinda Bencic of Switzerland, the gold medalist on the Tokyo Olympics, 7-6 (8), 6-3; Marketa Vondrousova ousted Karolina Pliskova 6-1, 6-2 in an all-Czech matchup; Sorana Cirstea of Romania beat Karolína Muchová of the Czech Republic 7-5, 6-1; and Varvara Gracheva of Russia defeated Magdalena Frech of Poland 6-1, 6-2.

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On the lads’s facet, Americans Tommy Paul and No. 10 Taylor Fritz superior in straight units.

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Paul beat Alejandro Davidovich Fokina of Spain 6-3, 7-5, helped by eight aces. Fokina had six double-faults.

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Fritz defeated Denis Shapovalov of Canada 6-4, 6-4. Shapovalov had seven double-faults.

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“It’s going to be a tough match I think for a round of 16,” Fritz mentioned. “Myself playing Holger (Rune) is a very tough draw. I’m excited to play him. We’ve never played before. I’m not entirely I guess sure what to make of his game. Obviously he’s very good.”

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Also, world No. 1 Carlos Alcaraz of Spain beat Dusan Lajovic of Serbia 6-0, 7-6 (5), world No. 8 Rune of Denmark defeated Diego Schwartzman of Argentina 6-4, 6-2, and Andrey Rublev of Russia dispatched Miomir Kecmanović of Serbian 6-1, 6-2.

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Later Sunday, Australian Open winner and world No. 2 Aryna Sabalenka of Belarus performs Marie Bouzkova of the Czech Republic, and world No. 4 Casper Ruud of Norway takes on Botic van de Zandschulp of the Netherlands.

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